Find the values of x and y and mark the answer accordingly.

I. (x^{2} - 529) = 0

II. y^{2} + 31y + 58 = 0

- x > y
- x < y
- x = y or the relation can't be established.
- x ≥ y
- x ≤ y

Option 3 : x = y or the relation can't be established.

Calculations:

I. (x2 - 529) = 0

⇒ x2 = 529

⇒ x = ±23

II. y2 + 31y + 58 = 0

⇒ y2 + 2y + 29y + 58 = 0

⇒ (y + 2) × (y + 29) = 0

⇒ y = -2, -29

**∴ The relation between x and y can't be established.**

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